Cupy a part of a string
Sorry, I guess this is extreme simple, but I couldn't found a answer for this. I simply like to take a part of a string and do a copy to another variable. I have ONLY the position as a number of the beginning of the sequence to copy, no string. And as well the length of the sequence to copy as number only. Is this possible without doing a loop? A loop would be way to slow. The data to process can become VERY big. Best rgds, Holger
posted by: Holger 25-Aug-2011/18:15:37-7:00
variable: copy/part "This String" 5 == "This "
posted by: Bert 26-Aug-2011/2:47:41-7:00
Well in this case, I would have only the /first/ five chars. So I would need to /navigate/ to the specific position, before I can get my string. Is there a way to tell rebol the beginning /and/ the length in only one step? Best rgds, Holger
posted by: Holger 26-Aug-2011/17:16:52-7:00
Try AT, >> t: "abcdefghijklm" == "abcdefghijklm" >> copy/part at t 5 3 == "efg" Means copy 3 chars from t starting AT char 5.
posted by: Endo 26-Aug-2011/18:39:01-7:00
Or make it a function: substr: func [arg [series!] start length][ copy/part at arg start length ] >> substr "test" 2 3 == est
posted by: Endo 26-Aug-2011/20:28:33-7:00
Thanx a lot!!! Best rgds, Holger :)
posted by: Holger 26-Aug-2011/21:01:14-7:00
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